Question

Write the balanced equation for the following. Action of dilute hydrochloric acid on sodium sulphide.

Answer 1

Hydrogen chloride gas:

• The chemical formula of Hydrogen chloride gas is $\mathrm{HCl}$.
• It is acidic in nature.

Sodium sulphide:

• The chemical formula of sodium sulphide is $\left({\mathrm{Na}}_2\mathrm{S}\right)$

The action of dilute hydrochloric acid on sodium sulphide:

• When dilute hydrochloric acid reacts with sodium sulphide Hydrogen sulphide gas is released.

${\mathrm{Na}}_2\mathrm{S}\left(\mathrm{s}\right)+2\mathrm{HCl}\left(\mathrm{aq}\right)\to 2\mathrm{NaCl}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)$

The balanced equation for the action of dilute hydrochloric acid on sodium sulphide:

${\mathrm{Na}}_2\mathrm{S}\left(\mathrm{s}\right)+2\mathrm{HCl}\left(\mathrm{aq}\right)\to 2\mathrm{NaCl}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)$

Elements name	The number of atoms on the reactant side	The number of atoms on the product side
$Na$	$2$	$2$
$S$	$1$	$1$
$H$	$2$	$2$
$Cl$	$2$	$2$

Here the number of atoms on the reactant side is equal to the number of atoms on the product side so this is a balanced equation.

The balanced equation for the action of dilute hydrochloric acid on sodium sulphide:

${\mathrm{Na}}_2\mathrm{S}\left(\mathrm{s}\right)+2\mathrm{HCl}\left(\mathrm{aq}\right)\to 2\mathrm{NaCl}\left(\mathrm{s}\right)+{\mathrm{H}}_2\mathrm{S}\left(\mathrm{g}\right)$