Multiply both equation with 12 as 12 is lcm of denominator of first equation.
so equation becomes
3x -2y =36
6x-12y =-24
equate coefficient of x by multiply first equation with 2,
6x-4y=72---(1)
6x-12y=-24---(2)
subtract (1)-(2)
-4y--12y =72--24
12y-4y = 96
8y=96
y=96÷8 = 12
substituting y value in second equation,
(X÷2)-y =-2
(x÷2) = -2+ y
= -2+ 12 = 10
x=2× 10= 20
so x=20 and y=12
like if satisfied