Question

$X$ is three times as old as $Y,Z$ was twice as old as $x$ four years ago. In the four year time, $x$ will be of $31$ years. What is the present age of $y$ and $z$.

• A. $9$ years, $46$ years
• B. $9$ years, $50$ years
• C. $10$ years, $46$ years
• D. $10$ years, $50$ years

Answer 1

The correct option is B $9$ years, $50$ years

let the age of $X=x,Y=y$ and $Z=z$

given $x=3y$

And four years ago

$z-4=2(x-4)$

After $4$ years

$x+4=31$;

$x=27$;

substituting above, we get

$y=9$ and $z=50$

Age of $Z=50$ and $Y=9$.