You are giving a patient $2.5 \frac{c c}{m i n}$ of a given solution intravenously. If this continues for $8$ hours, how many liters of this solution will you need?

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Solution

Determining the amount of solution required in liters
Given that the patient needs $2.5 \frac{c c}{m i n}$ for $8$ hours.
We know that $1 c c = 1 m l$
Therefore, converting we have,
$2.5 \frac{c c}{m i n} = 2.5 \frac{m l}{m i n}$
In $8$ hours, we have $8 \times 60 = 480 mins$ , therefore the total solution required would be,
$=$ $2.5 \frac{m l}{m i n} \times 480 m i n$
$=$ $1200 m l$
$=$ $1.2 l [∵ 1 l = 1000 m l]$
Thus, the amount of solution required in liters is $1.2 l$ .

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You are giving a patient 2.5ccmin of a given solution intravenously. If this continues for 8 hours, how many liters of this solution will you need?

You are giving a patient $2.5 \frac{c c}{m i n}$ of a given solution intravenously. If this continues for $8$ hours, how many liters of this solution will you need?