Question

Solve the equation.$\begin{array}{rcl}\frac{(2x+3)-(5x-7)}{6x+11}& =& \frac{-8}{3}\end{array}$

Answer 1

Find the value of $\mathrm{x}$:

$\begin{array}{rcl}\frac{(2\mathrm{x}+3)-(5\mathrm{x}-7)}{6\mathrm{x}+11}& =& \frac{-8}{3}\\ \frac{2\mathrm{x}+3-5\mathrm{x}+7}{6\mathrm{x}+11}& =& \frac{-8}{3}\\ \frac{-3\mathrm{x}+10}{6\mathrm{x}+11}& =& \frac{-8}{3}\\ 3\left(-3\mathrm{x}+10\right)& =& -8\left(6\mathrm{x}+11\right)\\ -9\mathrm{x}+30& =& -48\mathrm{x}-88\\ 48\mathrm{x}-9\mathrm{x}& =& -88-30\\ 39\mathrm{x}& =& -118\\ \therefore \mathrm{x}& =& \frac{-118}{39}\end{array}$

$\therefore$The value of$\mathrm{x}$ is$\frac{-118}{39}$.