**Answer:**

Given parameters

Mass of the engine (M) = 8000 kg

Number of wagons = 5

Mass of the wagons (m) = 2000 kg

Force exerted by the engine (F ) = 40000 N

Frictional force offered by the track (F_{f}) = 5000 N

(a) Net force (F_{a}) = F – F_{f}

F_{a }= 40000 N – 5000 N

**F _{a }= 35000 N**

(b) Let us consider the acceleration of the train to be a m/s^{2}

Acceleration is the ratio of net acceleration force by mass, i.e.

a = F_{a}/m

Where m is the mass of the train, it can be calculated as follows

The total mass of the train (m) = Mass of the engine + (Mass of the wagons × Number of wagons)

m = 8000 + (5 × 2000)

m = 18000 kg

Acceleration of the train (a) = 35000/18000

**a = 1.944m/s ^{2}**

(c) F_{21} = m_{4w} × a

- F
_{21}= Force applied on Wagon 2 by Wagon 1 - m
_{4w}= mass of 4 wagons - a = acceleration of the train

The force of wagon 1 on wagon 2 = Force of wagon 2 on wagon 1

⇒ (4 × 2000 × 1.944)

= 15552 N

∴ The force of wagon-1 on the wagon-$2 is 15552 N.$

Really help to me to understand

It really helped members

It really helped me

really helped

really helped

It really helped me

thanks, it was really helpful

It was really helpful

good

really helped

Nice one

Thanks

Thankyou!

It was helpful.