Since iron is more reactive than copper, it displaces copper, resulting in FeSO4. A portion of the iron is dissolved during this process, resulting in holes in the pot.
Fe + CuSO4 → FeSO4 + Cu
In this reaction following two processes take place:
- Cu²⁺ + 2e = Cu⁰ (reduction process, Cu²⁺ is the oxidizing agent)
- Fe⁰ – 2e = Fe²⁺ (oxidation process, Fe⁰ is the reducing agent)
The reaction can be a double displacement reaction as well as a redox reaction (oxidation and reduction both take place simultaneously).