A solution of CuSO4 was kept in an iron pot. After a few days, the iron pot was found to have a number of holes in it. Explain the reason in terms of reactivity. Write the equation of the reaction involved.

Answer:

Since iron is more reactive than copper, it displaces copper, resulting in FeSO4. A portion of the iron is dissolved during this process, resulting in holes in the pot.

Fe + CuSO4 → FeSO4 + Cu

In this reaction following two processes take place:

  • Cu²⁺ + 2e = Cu⁰ (re­duc­tion process, Cu²⁺ is the ox­i­dizing agent)
  • Fe⁰ – 2e = Fe²⁺ (ox­i­da­tion process, Fe⁰ is the re­duc­ing agent)

The reaction can be a double displacement reaction as well as a redox reaction (oxidation and reduction both take place simultaneously).

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