Daniel is paining the walls and ceiling of a cuboidal hall with length, breadth and height of 15 m, 10 m and 7 m respectively. From each can of paint 100 m^2of area is painted. How many cans of paint will she need to paint the room?

Solution:

Given

Length of wall (l) = 15 m, 

Breadth of wall (b) = 10 m 

Height of wall, (h) = 7 m

Find out

We have to find out the number of cans required

Solution

Total Surface area of classroom = 2 × (lb + bh + hl) – lb

= 2 × (15 × 10 + 10 × 7 + 7 × 15) – (15 × 10) 

= 2 × (150 + 70 + 105) – 150

= 650 – 150

= 500

Now, Required number of cans = Area of hall/Area of one can

= 500/100 = 5

Answer

Thus, 5 cans are required to paint the room.

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