For an angular projection given to a projectile, find :
i. Maximum height:
Step 1: Given data
It is the maximum vertical height attained by the object above the point of projection during its flight denoted by . At maximum height, the projectile will only have a vertical component.
From the diagram, the initial speed will be
The acceleration will be .
The final velocity will be
Step 2: Find the displacement
Using the third equation of motion,
where is the initial speed, is the final speed, is the acceleration, is the displacement, is the acceleration due to gravity.
ii. Time of flight:
Step 1: Given data
The final displacement in the y-direction is 0
The acceleration will be .
Step 2: Find the time
Using the equation of motion,
iii. Horizontal range:
Step 1: Given
To calculate the range, we will consider only the horizontal component.
Step 2: Find the range
Distance = Speed x Time
Substituting the value of from (1).
Hence,