How to prepare a 1N HCl solution in 100 ml?

Answer:

We know that Normality of HCL is 12N

According to the formula

N₁V₁= N₂V₂

N₁ = 12N

V₁= ?

N₂ = 1N (Given)

V₂ = 100 ml

Substituting the values in the above formula we get

12 X V₁ = 1 X 100

V₁= 8.33mL

If we add 8.33mL in 100 L of water we get 1 N HCl.