The value of tan203°+tan22°+tan203°tan22° is
1
-1
2
0
Finding the value of function:
Here we use the formula tan(A+B)=tanA+tanB1-tanAtanB
tan225°=tan(203°+22°)=tan(180°+45°)=tan45°=1
tan(203°+22°)=tan203°+tan22°1-tan203°tan22°=1tan203°+tan22°=1-tan203°tan22°tan203°+tan22°+tan203°tan22°=1
Hence option(A) is the correct answer .