Question

What is the angular momentum of an electron in d orbital?

Answer 1

Step1. Formula of angular momentum(L)

$L=\sqrt{l\left(l+1\right)}\frac{h}{2\mathrm{\pi }}$

Here, l is the azimuthal quantum number, and h is the Planck constant.

Step2. Calculation of angular momentum of an electron in d orbital

• The value of l for d-orbital is two.
• $$\begin{gathered} L=\sqrt{2\left(2+1\right)}\frac{h}{2\mathrm{\pi }} \\ =\sqrt{6}\frac{h}{2\mathrm{\pi }} \end{gathered}$$

Hence, the angular momentum of the electron in ‘d’ orbital is equal to $\sqrt{6}\frac{h}{2\mathrm{\pi }}$.