wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

0.22 g of a hydrocarbon (i.e., a compound containing carbon and hydrogen only) on complete combustion with oxygen gave 0.9 g water and 0.44 g carbon dioxide. Are these results in accordance with the law of conservation of mass (atomic mass of C = 12, H = 1, O = 16).


A

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

True


Carbon and hydrogen in the hydrocarbon on combustion form carbon dioxide and water. From the formulae of CO2­ and H2O, the weights of carbon and hydrogen contained in 0.44 g CO2 and 0.9 g water, respectively, can be calculated as under:
Molecular weight of CO2­ = 12 + 32 = 44
Molecular weight of H2O = 2 + 16 = 18
Weight of carbon in 0.44 g of CO2­ = 12×0.4444 = 0.12 g

Weight of carbon in 0.9 g of H2­O = 2 × 0.918 = 0.10 g
Total weight of C and H in the hydrocarbon after combustion = 0.12 + 0.10 = 0.22 g
Since the weight of carbon and hydrogen after combustion is the same as the weight of hydrocarbon

(containing carbon and hydrogen only) after combustion, the results are in accordance with the law of conservation of mass.


flag
Suggest Corrections
thumbs-up
12
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Laws of Chemical Combination
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon