Question

10 g of a gas at 2 atm pressure is cooled from ${273}^{o}C$ to 273K. Keeping its volume constant. The pressure of the gas will be equal to ___ atm.

Answer 1

Let the volume be V.

$Now,\frac{P_1}{T_1}=\frac{P_2}{T_2}\therefore P_2=\frac{P_1\times T_2}{T_1}$

$=\frac{2\times 273}{546}=0.5atm$