Two bodies are projected simultaneously with the same velocity of 19.6 m/s from the top of a tower , one vertically upwards and the other vertically downwards. As they reach the ground, the time gap is

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Solution

Given,
Initial velocity = 19.6 m/s
When the body will reach the highest point then its velocity will be zero
Final velocity = 0

From the equation of motion
$v = u + a t$
$O r, 0 = 19.6 - 9.8 \times t$
$O r, t = 2 s e c$
So we can say that in 2-sec body will reach the highest point and in the next 2-sec body will reach to the point from which the second body is thrown in the downward direction.

So we can say that the time gap between the two bodies in reaching the ground is 4 sec.

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