5 $m l$ of a gaseous hydrocarbon( $C_{x} H_{y}$ ) was exploded with 30 $m l$ of oxygen. The resulting gas on cooling to room temperature is found to measure 25 $m l$ of which 10 $m l$ are absorbed by $N a O H$ and the remainder by pyrogallol. The value of x+y is?

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Solution

Balanced equation
$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} ⟶ x C O_{2} + \frac{y}{2} H_{2} O_{(l)}$

5 $m L$ 30 $m L$

0 $30 - 5 (x + \frac{y}{4})$

5x

since 5x=10 $\Rightarrow$ x=2

$30 - 5 (x + \frac{y}{4}) = 15 \Rightarrow y = 4$

Therefore formula of hydrocarbon = $C_{x} H_{y}$

x + y = 2 + 4 = 6

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5 $m l$ of a gaseous hydrocarbon( $C_{x} H_{y}$ ) was exploded with 30 $m l$ of oxygen. The resulting gas on cooling to room temperature is found to measure 25 $m l$ of which 10 $m l$ are absorbed by $N a O H$ and the remainder by pyrogallol. The value of x+y is?

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