Acidic Buffer Action
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How is cell potential affected by concentration ?
pH of a 10−3 M solution of hydrochloric acid will be
1.3
2.0
3.0
4.5
What is the Amount of heat evolved when of is mixed with of solution?
8×10−12M
8×10−10M
8×10−11M
8×10−13M
- 5.74
- 4.74
- 4.1
- None of these
- 1:10000
- 1000:1
- 10000:1
- 100:1
Identify the parent acids and bases of the following salts. Name each salt. .
In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is _________ M. (Round off to the Nearest Integer).
[Given: pKa (acetic acid) = 4.74]
- 0.328 g
- 0.458 g
- 4.19 g
- 3.28 g
Which of the following salts will dissolve in water to produce a solution having a pH below 7?
- 10 mL
- 25 mL
- 40 mL
- 50 mL
- 0.3 M aqueous glucose solution
- 0.15 M aqueous Na2SO4 solution showing complete dissociation
- 0.15 M aqueous KHF2 solution showing complete dissociation
- 0.1 M aqueous BaCl2 solution showing 80% dissociation
- 1 : 10
- 5 : 4
- 10 : 1
- 4 : 5
- Ammonium chloride and ammonium hydroxide
- Sulphuric acid and sodium sulphate
- Sodium chloride and sodium hydroxide
- Sodium acetate and acetic acid
Dissociation constant Ka of propionic acid at 25∘C is 1.34×10−5
(Take log(1.34)=0.13)
- 4.09
- 4.95
- 5.15
- 5.87
log (1.8)=0.255, log (0.66)=−0.181
- 9.04
- 4.56
- 7.2
- 6.5
Dissociation constant of propionic acid Ka at 25∘C is 1.34×10−5
Take log(1.34)=0.13
- 0.1 mol
- 0.2 mol
- 0.01 mol
- 0.02 mol
- 8.00
- 10.00
- 4.50
- 7.00
- 7.33
- 0.733
- 0.136
- 1.36
An acidic buffer solution can be prepared by mixing the solutions of
Sulphuric acid and sodium hydroxide
Sodium chloride and sodium hydroxide
Ammonium acetate and acetic acid
Ammonium chloride and ammonium hydroxide
(pKa = 4.74, log 4 =0.6)
- 5.04, 5.04
- 5.04, 0.504
- 5.34, 0.534
- 5.34, 5.34
- 10 mL
- 25 mL
- 40 mL
- 50 mL
- HCl and CH3COONa
- HNO3 and CH3COOH
- H2SO4 and CH3COONa
- CH3COOH and CH3COONa
- pH = 4.7
- pH = 5
- pOH = 9
- pOH = 9.3
When pKa of acetic acid is 4.752.
log 32.96=1.518
- 25
- 10
- 23
- 33
(Consider heat capacity of all solutions as 4.2 Jg−1K−1 and density of all solutions as 1.0 gmL−1)
The pH of the solution after Expt. 2 is:
- 2.8
- 4.7
- 5
- 7
- 7
- 4.2
- 6.3
- 5.8
take log 1.30=0.114, log 0.652=−0.186
- 7
- 5.65
- 3.24
- 4.7
The dissociation constant for CH3COOH is 1.8×10−5.
- 6.88
- 4.92
- 3.68
- 5.76