Ellingham Diagram
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ΔG=0 and melting or boiling point of the metal oxide.
ΔG<0 and decomposition of the metal oxide.
ΔG=0 and reduction of the metal oxide.
ΔG>0 and decomposition of the metal oxide.
value of activation energy for the reaction is
kJ mol−1 (Nearest integer)
(Given: R = 8.31 JK−1mol−1)
Which metal has the highest thermal expansion?
Out of C andCO1 which is a better reducing agent at 673 K?
- ΔG is negative
- ΔH is negative
- Δs is positive
- Δs is negative
i. Zn(s)+12O2 (g)→ZnO(s); ΔG=−360 KJ/mol
ii. C(s)+12O2 (g)→CO(s); ΔG=−460 KJ/mol
Then choose the correct statement from the following
- Zinc can be oxidized by CO
- ZnO can be reduced by C
- ZnO can be reduced by CO
- None of the above
Statement I : The choice of reducing agents for metals extraction can be made by using Ellingham diagram , a plot of ΔGo vs temperature.
Statement II : The value of ΔS increases from left to right in Ellingham diagram .
In the light of the above statements , choose the most appropriate answer from the options given below :
Column I | Column II |
A. Self reduction | P. Lead |
B. Carbon reduction | Q. Silver |
C. Complex formation and displacement by metal | R. Copper |
D. Electrolytic reduction | S. Sodium |
- A→P, R; B→P; C→Q; D→S
- A→P; B→P, R; C→Q; D→S
- A→Q; B→S, R; C→Q; D→P
- A→R, S; B→P; C→Q; D→R
The carbon – based reduction method is not used for the extraction of
tin from SnO2
iron from Fe2O3
aluminium from Al2O3
magnesium from MgCO3, CaCO3
Fe3+(aq)+e−→Fe2+(aq) E∘=+0.771 V
Fe2+(aq)+2e−→Fe(s) E∘=−0.447 V
Calculate E∘ for the half-cell reaction Fe3+(aq)+3e−→Fe(s).
- +0.32 V
- +1.22 V
- −0.04 V
- +0.04 V
- Electrolysis
- Thermal reduction
- Vapour phase refining
- Zone refining
- Below 1073 K, C is a better reducing agent.
- Below 1073 K, CO is a better reducing agent.
- Above 1073 K, C is a better reducing agent.
- Haematite can’t be reduced by C or CO.
Give an example of a chemical reaction in which a tremendous amount of heat is released.
Pb, Au, Mg, Sn, Fe, Al, Ag, Hg, Na, Zn, Cu, Ca
The point of intersection and sudden increase in the slope, in the diagram given below respectively, indicates:
ΔG = 0 and melting or boiling point of the metal oxide.
ΔG < 0 and decomposition of the metal oxide.
ΔG = 0 and reduction of the metal oxide.
ΔG > 0 and decomposition of the metal oxide.
- Reduction with carbon
- Reduction with aluminium
- Electrolytic reduction
- Reduction with CO
Pb, Au, Mg, Sn, Fe, Al, Ag, Hg, Na, Zn, Cu, Ca
- ΔG vs T
- (ΔG−TΔS) vs T
- ΔH vs T
- ΔG vs P
- pyrolysis of Bl3 (Van Arkel).
- reducing BCl3 with H2.
- electrolysis of fused BCl3.
- thermal decomposition of B2H6.
Which of the following is incorrect on the basis of the above Ellingham diagram for carbon?
- Up to 710∘C, the reaction of formation of CO2 is energetically more favorable, but above 710∘C, the formation of CO is preferred.
- In principle, carbon can be used to reduce any metal oxide at a sufficiently high temperature.
- ΔS(C(s)+12O2(g)→CO(g))<ΔS(C(S)+O2(g)→CO2(g))
- Carbon reduces many oxides at elevated temperature because ΔG∘ vs temperature line has a negative slope.
- Below 1073 K, C is a better reducing agent.
- Below 1073 K, CO is a better reducing agent.
- Above 1073 K, C is a better reducing agent.
- Haematite can’t be reduced by C or CO.
Column I | Column II | ||
(a) | Cyanide process | (i) | Ultrapure Ge |
(b) | Froth floatation process | (ii) | Dressing of ZnS |
(c) | Electrolytic reduction | (iii) | Extraction of Al |
(d) | Zone refining | (iv) | Extraction of Au |
(v) | Purification of Ni |
- a - (iv), b - (ii), c - (iii), d - (i)
- a - (ii), b - (iii), c - (i), d - (v)
- a - (i), b - (ii), c - (iii), d - (iv)
- a - (iii), b - (iv), c - (v), d - (i)
- Positive value of ΔfG∘ for MxO indicates, MxO decompose on its own
- Metal with most -ve value of ΔG∘ for formation of oxide can act as a better reducing agent
- ΔG∘ is plotted for the oxidation of metal with 1 mole of O2
- ΔG∘ is plotted for reduction of 1 mole of metal oxide
- Mg
- Fe
- Cu
- Zn
- Al2O3
- Cu2O
- MgO
- ZnO