Identification of Different Process
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Q.
Which of the following is true for an isothermal process?
d V = 0
d P = 0
d T = 0
d Q = 0
Q. Two moles of a perfect gas undergo the following processes
(i) a reversible isobaric expansion from (1.0 am, 20.0L) to (1.0 atm, 40.0 L)
(ii) a reversible isochoric change of state from (1.0 atm, 40.0 L) to (0.5 atm, 40.0 L);
(iii) a reversible isothermal compression from (0.5 am, 40.0 L) to (1.0 atm, 20.0 L)
What is the total heat exchange here in Joules?
ln2=0.7, ln3=1.1, R=1/12 L atm/mol, 25/3 J/mol K, 1L atm=101 J
(i) a reversible isobaric expansion from (1.0 am, 20.0L) to (1.0 atm, 40.0 L)
(ii) a reversible isochoric change of state from (1.0 atm, 40.0 L) to (0.5 atm, 40.0 L);
(iii) a reversible isothermal compression from (0.5 am, 40.0 L) to (1.0 atm, 20.0 L)
What is the total heat exchange here in Joules?
ln2=0.7, ln3=1.1, R=1/12 L atm/mol, 25/3 J/mol K, 1L atm=101 J
Q.
The Carnot cycle has maximum efficiency for:
Reversible engine
Irreversible engine
Petrol engine
Diesel engine
Q. A fixed mass 'm' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.
The succeding operation that enable this transformation of states are
The succeding operation that enable this transformation of states are
- Heating, cooling, heating, cooling
- Cooling, heating, cooling, heating
- Heating, cooling, cooling, heating
- Cooling, heating, heating, cooling
Q. The polytropic process for an ideal gas is given as PVn=constant. For this process, the expression for the work obtained is:
W=P1V1[(V2V1)x−1](y)
What is the value of (x+y)?
W=P1V1[(V2V1)x−1](y)
What is the value of (x+y)?
Q. The process, in which no heat enters or leaves the system, is termed as
- Adiabatic
- Isobaric
- Isochoric
- Isothermal
Q. Two moles of a perfect gas undergo the following processes
I. A reversible isobaric expansion from (1.0 atm. 20 L) to (1.0 atm, 40 L)
II. A reversible isochoric exansion from (1.0 atm, 40 L) to (0.5 atm, 40 L)
III. A reversible isothermal compression from (0.5 atm, 40 L) to (1.0 atm. 20 L)
Calculate the total work done (W) involved in the above processes.
I. A reversible isobaric expansion from (1.0 atm. 20 L) to (1.0 atm, 40 L)
II. A reversible isochoric exansion from (1.0 atm, 40 L) to (0.5 atm, 40 L)
III. A reversible isothermal compression from (0.5 atm, 40 L) to (1.0 atm. 20 L)
Calculate the total work done (W) involved in the above processes.
- -620.77 J
- 620.77 J
- -120.77 J
- 120.77 J
Q.
What are the properties of perfect gas?
Q. The process, in which no heat enters or leaves the system, is termed as
- Isochoric
- Isobaric
- Isothermal
- Adiabatic
Q. In thermodynamics, the P−V work done is given by w=−∫dVPext. For a system undergoing a particular process, the work done is,
w=−∫dV(RTV−b−aV2)
This equation is applicable to a- System that satisfies the van der Waals equation of state.
- Process that is reversible and adiabatic.
- Process that is irreversible and at constant pressure.
- Process that is reversible and isothermal.
Q. Temperature of a system decreases during
- Adiabatic compression
- Isothermal compression
- Adiabatic expansion
- Isothermal expansion
Q. A real gas is expected to exhibit maximum deviations from ideal gas law at:
- low T and low P
- low T and high P
- high T and high P
- high T and low P
Q. 1 mole of CO2 gas at 300 K is expanded under reversible adiabatic condition such that its volume becomes 27 times.
(a) What is the final temperature
(b) What is work done?
Given γ=1.33 and CV=25.08 Jmol−1K−1 for CO2.
(a) What is the final temperature
(b) What is work done?
Given γ=1.33 and CV=25.08 Jmol−1K−1 for CO2.
Q. During adiabatic expansion of an ideal gas
Q. Three moles of an ideal gas initially at 27oC and 40 L volume are compressed isothermally and reversibly till the final volume of the gas is 10 L. Calculate q for the process.
Take:
log(0.25)=0.602
Take:
log(0.25)=0.602
- −3.65 kJ
- −23.2 kJ
- −10.37 kJ
- −7.81 kJ
Q. A fixed mass'm' of a gas is subjected to transformation of states from K to L to M to N and back to K as shown in the figure.
The pair of isochoric processes among the transformation of states is
The pair of isochoric processes among the transformation of states is
- M to N and N to K
- L to M and N to K
- L to M and M to N
- K to L and L to M
Q. 1 mole of CO2 gas at 300 K is expanded under a reversible adiabatic condition such that its volume becomes 27 times.
(a) What is the final temperature? (b) What is the work done?
(Given γ = 1.33 and Cv = 25.08 J mol−1K−1 for CO2)
(a) What is the final temperature? (b) What is the work done?
(Given γ = 1.33 and Cv = 25.08 J mol−1K−1 for CO2)
Q. Carbon monoxide is allowed to expand isothermally and reversibly from 10 m3 to 20 m3 at 300 K and work obtained is 4.754 kJ. Calculate the number of moles of carbon monoxide
- 27.5 mol
- 5.5 mol
- 2.75 mol
- 55.0 mol
Q. 1 mole of an ideal non-linear triatomic gas is adiabatically expanded from 16 atm, 300K to 1 atm. Calculate q, W, ΔU, ΔH if process is carried out reversibly.
Q. In an adiabatic process the quantity which remains constant is:
- total heat of system
- tempertature
- volume
- pressure
Q. Assertion :The heat absorbed during the isothermal expansion of an ideal gas against vacuum is zero. Reason: The volume occupied by the molecules of an ideal gas is zero.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Q. In thermodynamics, the P−V work done is given by w=−∫dVPext. For a system undergoing a particular process, the work done is,
w=−∫dV(RTV−b−aV2)
This equation is applicable to a- System that satisfies the van der Waals equation of state.
- Process that is reversible and isothermal.
- Process that is reversible and adiabatic.
- Process that is irreversible and at constant pressure.
Q. The polytropic process for an ideal gas is given as PVn=constant. For this process, the expression for the work obtained is:
W=P1V1[(V2V1)x−1](y)
What is the value of (x+y)?
W=P1V1[(V2V1)x−1](y)
What is the value of (x+y)?
Q.
Which of the following is true for an isothermal process?
d Q = 0
d V = 0
d P = 0
d T = 0
Q.
Which of the following is zero for an isochoric process
- dT
- dE
- dV
- dP
Q. In each of the following question, an Assertion (A) is followed by a corresponding Reason (R). Use the following keys to choose the appropriate answer:
Assertion (A): The heat absorbed during the isothermal expansion of an ideal gas against vacuum is zero.
Reason (R): The volume occupied by the molecules of an ideal gas is zero.
Assertion (A): The heat absorbed during the isothermal expansion of an ideal gas against vacuum is zero.
Reason (R): The volume occupied by the molecules of an ideal gas is zero.
- If both (A) and (R) are correct, and (R) is the correct explanation for (A).
- If the both (A) and (R) are correct, but (R) is not the correct explanation for (A).
- If (A) is correct, but (R) is incorrect.
- If (A) is incorrect, but (R) is correct.
- If both (A) and (R) are incorrect.
Q.
Three mole of Ag is heated from 300 K to 1000 K. Calculate ΔH when P = 1 atm and
62 kJ/mol
45 kJ/mol
38 kJ/mol
54 kJ/mol
Q. In each of the following question, an Assertion (A) is followed by a corresponding Reason (R). Use the following keys to choose the appropriate answer:
Assertion (A): The heat absorbed during the isothermal expansion of an ideal gas against vacuum is zero.
Reason (R): The volume occupied by the molecules of an ideal gas is zero.
Assertion (A): The heat absorbed during the isothermal expansion of an ideal gas against vacuum is zero.
Reason (R): The volume occupied by the molecules of an ideal gas is zero.
- If both (A) and (R) are correct, and (R) is the correct explanation for (A).
- If the both (A) and (R) are correct, but (R) is not the correct explanation for (A).
- If (A) is correct, but (R) is incorrect.
- If (A) is incorrect, but (R) is correct.
- If both (A) and (R) are incorrect.
Q. If true enter 1, if false enter 0.
Gases having Vm>22.4 are more compressible
Gases having Vm>22.4 are more compressible
- 1
Q. Two moles of a perfect gas undergo the following processes
I. A reversible isobaric expansion from (1.0 atm. 20 L) to (1.0 atm, 40 L)
II. A reversible isochoric exansion from (1.0 atm, 40 L) to (0.5 atm, 40 L)
III. A reversible isothermal compression from (0.5 atm, 40 L) to (1.0 atm. 20 L)
Calculate the total work done (W) involved in the above processes.
I. A reversible isobaric expansion from (1.0 atm. 20 L) to (1.0 atm, 40 L)
II. A reversible isochoric exansion from (1.0 atm, 40 L) to (0.5 atm, 40 L)
III. A reversible isothermal compression from (0.5 atm, 40 L) to (1.0 atm. 20 L)
Calculate the total work done (W) involved in the above processes.
- -620.77 J
- 620.77 J
- -120.77 J
- 120.77 J