Kirchhoff's Junction Law
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- Zero
- 50 V
- 200 V
- 400 V
In the figure shown, the current in the 10 V battery is close to
from positive to the negative terminal
from negative to the positive terminal
from positive to the negative terminal
from positive to the negative terminal
- 20 V and 2.0 mA
- 10 V and 0.5 mA
- Zero volt and therefore no current
- 20 V and 0.5 mA
Two resistors X and Y of resistances and respectively are first joined in parallel and then in series. In each case, the voltage supplied is .
(i) Draw the circuit diagram to show the combination of resistors in the parallel connection.
(ii) Calculate the voltage across the resistor in the series combination of resistors.
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/15092/content_26.png)
- 1 A
- 2.5 A
- 0.4 A
- 3 A
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/931716/original_Q9.png)
- 10 V
- 15 V
- 18 V
- 20 V
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/917026/original_Q9.png)
- 4 V
- 3 V
- 2.5 V
- 0 V
Kirchhoffs first law is based on?
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/17250/content_imageedit_41_2337599430.png)
- None of these
- 0.1
- 0.3
- 0.6
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/15098/content_29.png)
- 23 A
- – 3 A
- 3 A
- 13 A
- 11.4 V and 11.5 V
- 11.7 V and 11.8 V
- 11.6 V and 11.7 V
- 11.5 V and 11.6 V
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1517123/original_PYQ_mains_2020_9__jan_evng_6.png)
- QA=CVe, QB=CV2
- QA=CV, QB=CV
- QA=CV, QB=CVe
- QA=CV2, QB=CVe
- m=8, n=3
- m=6, n=4
- m=12, n=2
- m=2, n=12
![](https://s3-us-west-2.amazonaws.com/infinitestudent-images/ckeditor_assets/pictures/16135/content_1.png)
- 4V
- 6V
- 8V
- 10V
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1524728/original_33.png)
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/617209/original_Q13.png)
- ε1−(i1+i2)R−i1r1=0
- ε2−i2r2−ε1−i1r1=0
- −ε2−(i1+i2)R+i2r2=0
- ε1−(i1+i2)R+i1r1=0
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1236607/original_5q.png)
- 5 V and 10 V
- 10 V and 5 V
- 20 V and 10 V
- 10 V and 20 V
![](https://search-static.byjusweb.com/question-images/byjus/infinitestudent-images/ckeditor_assets/pictures/609543/original_Q20.png)
- R3
- 2R3
- 4R3
- 3R4
How is potential gradient measured?
There are lamps in a hall.
Each one of them can be switched on independently.
The number of ways in which the hall can be illuminated is?
- 3.25 V
- 4.55 V
- 6.75 V
- 12.50 V
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1324211/original_7.qstn.png)
- r
- r4
- r2
- 5r8
- RL
- RL
- LR
- 1LR
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/765912/original_7.png)
![](https://search-static.byjusweb.com/question-images/byjus/ckeditor_assets/pictures/1034603/original_29.png)
![](https://df0b18phdhzpx.cloudfront.net/ckeditor_assets/pictures/1249829/original_37.png)
- 24 μC
- 12 μC
- 16 μC
- 9 μC