Laws of Mass Conservation
Trending Questions
What are the Limitations of the law of conservation of mass?
- 142 g
- 126 g
- 118 g
- 104 g
0.22 g of a hydrocarbon (i.e., a compound containing carbon and hydrogen only) on complete combustion with oxygen gave 0.9 g water and 0.44 g carbon dioxide. Are these results in accordance with the law of conservation of mass (atomic mass of C = 12, H = 1, O = 16).
True
False
- 11.65 g
- 23.3 g
- 25.5 g
- 30.6 g
- Law of conservation of mass
- Law of definite proportions
- Law of multiple proportions
- None of these
Show that following equations are in accordance with the law of conservation of mass:
()
- 11 g
- 12 g
- 13 g
- 10 g
Calculate the molecular mass of Ethylene ()
CuSO4.5H2O→CuSO4+5H2O
CuSO4+2KCN→Cu(CN)2+K2SO4
2Cu(CN)2→2CuCN+(CN)2
2CuCN+6KCN→2K3[Cu(CN)4]
(Molar mass of K=39 g/mol, Cu=63.5 g/mol)
- 122.4 g
- 49.9 g
- 12.24 g
- 19.96 g
(Molar mass of K = 39 g/mol, Fe = 56 g/mol, Zn = 65 g/mol)
- 15.85 g
- 10.67 g
- 6.35 g
- 20.74 g
Balance the following chemical equation:
Fe + H2O → Fe3O4 + H2
When of Barium chloride is added with of Sodium sulphate, of Barium sulphate and of Sodium chloride are formed. Show that these observations are in agreement with the law of conservation of mass.
47 g of impure Al2O3 is reduced electrolytically to give aluminium and oxygen. Calculate the amount of aluminium produced.
- Precipitation reactions
- Nuclear reactions
- Decomposition reactions
- Neutralization reactions
A chemical equation is balanced according to the law of
Conservation of mass
Multiple proportions
Constant proportions
Reciprocal proportions
of sucrose is dissolved in water in a beaker. The number of oxygen atoms in the solution is-
Five grams of KClO3 yield 3.041 g of KCl and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of ±0.4% error?
True
False
(Molar mass of Ti = 48 g/mol)
- 6 g
- 2 g
- 4 g
- 8 g
- 104 g
- 118 g
- 126 g
- 142 g
SO2(g)+Cl2(g)+2H2O→H2SO4(l)+2HCl(l)
H2SO4(l)+BaCl2→BaSO4↓+2HCl
112 g of sulphur is burned initially to form SO2. Find the amount of BaSO4 precipitate obtained in the series of reactions.
(Molar mass of Ba = 137 g/mol)
- 815.5 g
- 456.3 g
- 635.7 g
- 988.1 g
(Molar mass of K = 39 g/mol, Fe = 56 g/mol, Zn = 65 g/mol)
- 15.85 g
- 10.67 g
- 6.35 g
- 20.74 g