Dropping Objects
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A body dropped from top of a tower fall through 40 m during the last two seconds of its fall. The height of the tower is
(g=10 m/s2)
- 90 m
- 45 m
- 55 m
- 60 m
- 60 m
- 45 m
- 80 m
- 50 m
A body falls freely from rest. It covers as much distance in the last second of its motion as covered in the first three seconds. The body has fallen for a time;
3s
5s
7s
9s
A motor car moving with a uniform speed of 20 ms−1 comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is
20m/sec2
−20m/sec2
−40m/sec2
+2m/sec2
- 1.5
- 1
- 0.50
- 0.25
- 4.9 m
- 9.8 m
- 19.6 m
- 24.5 m
- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m
- T=2hV
- T=√2hg+hV
- T=√2hg−hV
- T=√h2g+2hV
- 6 s
- 5 s
- 7 s
- 4 s
- 358 m
- 318 m
- 278 m
- 258 m
A body is released from a great height and falls freely towards the earth. Another body is released from the same height exactly one second later. The separation between the two bodies, two seconds after the release of the second body is
4.9 m
9.8 m
19.6 m
24.5 m
A stone dropped from the top of the tower touches the ground in 4 sec. The height of the tower is about
80 m
40 m
20 m
160 m
- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m
- h9 m
- 7h9 m
- 8h9 m
- 17h18 m
- a:b
- b:a
- √a:√b
- a2:b2
- 80 m
- 96 m
- 64 m
- 78 m
- 1
- 2
- 3
- None of these
- h9 metres from the ground
- 7h9 metres from the ground
- 8h9 metres from the ground
- 17h18 metres from the ground
A ball is dropped from a height of 5 m. Find the velocity with which it hits the ground.
10 m/s
√−100m/s
5 m/s
- 10 m/s
- 58.6 m
- 14.7 m
- 18.9 m
- 24.3 m
- 4.9 m
- 9.8 m
- 19.6 m
- 24.5 m
- Both A and B will reach the ground simultaneously
- Ball A will hit the ground, 2 s after B hits the ground
- Both the balls will hit the ground with the same velocity
- Both the balls will hit the ground with the different velocity
- 45
- 54
- 125
- 512
If I drop a ball from a height of 5 m then how long will it take to reach the ground?
1
2
3
5
A motor car moving with a uniform speed of 20 ms−1 comes to rest on the application of brakes after travelling a distance of 10 m. Its acceleration is
20m/sec2
−20m/sec2
−40m/sec2
+2m/sec2
- 78.4 m
- 64.2 m
- 98.6 m
- 116.8 m
- 2.8 s
- 3.4 s
- 3.8 s
- 4.2 s
If I dropped a Metal ball of weight 10kg and a feather and If I can Imagine that there is no air resistance, then, . Which do you think will reach the ground first?
The 10kg ball
feather
they will land together
I tried and don't have an answer
- 2 sec
- 3 sec
- 4 sec
- None of these
A body A is thrown vertically upward with the initial velocity v1. Another body B is dropped from a height h. Find how the distance x between the bodies depends on the time t if the body begin to move simultaneously.
- x=(h−v1)t
- x=h−v1t
- x=h−v1t
- x=ht−v1