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Standard XII

Physics

Collision Example II

A 0.5 kg ba...

Question

A $0.5 k g$ ball moving with a speed of $12 m / s$ strikes a hard wall and return back with same velocity. Find change in momentum.

12 kg m/s

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20 kg m/s

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22 kg m/s

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120 kg m/s

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Solution

The correct option is A 12 kg m/s
Change in momentum $= m ({\to v}_{2} - {\to v}_{1})$
$\Rightarrow Δ p = 0.5 [12 - (- 12)]$
$\Rightarrow Δ p = 0.5 \times 24 = 12 k g m / s$

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A 0.5 kg ball moving with a speed of 12m/s strikes a hard wall and return back with same velocity. Find change in momentum.

The correct option is A 12 kg m/sChange in momentum =m(→v2−→v1) ⇒Δp=0.5[12−(−12)]⇒Δp=0.5×24=12kgm/s

A $0.5 k g$ ball moving with a speed of $12 m / s$ strikes a hard wall and return back with same velocity. Find change in momentum.

The correct option is A 12 kg m/s
Change in momentum $= m ({\to v}_{2} - {\to v}_{1})$
$\Rightarrow Δ p = 0.5 [12 - (- 12)]$
$\Rightarrow Δ p = 0.5 \times 24 = 12 k g m / s$