A 10,000 kg engine exerts a force of 50 kN, to pull 4 wagons along the track as shown. If the track offers an opposing frictional force of 5 kN, calculate the acceleration of the train.
A
2.5m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2.25m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
3.5m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
3.25m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B2.25m/s2 Total mass of train, M=Mengine+4Mwagon M=10,000+4×2500 M=20,000kg
Net force acting on the train is: Fnet=Ftrain−Ffriction Fnet=(50−5)kN Fnet=45kN
Applying Newton’s second law, Fnet=Ma 45kN=20000a a=4500020000 a=2.25m/s2
Therefore, the acceleration of the train is 2.25m/s2.