A bag contains three green marbles, four blue marbles, and two orange marbles. If a. marble is picked at random,then the probability that it is not an orange marble is

\frac{1}{4}

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\frac{1}{3}

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\frac{4}{9}

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\frac{7}{9}

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Solution

The correct option is D $\frac{7}{9}$
Total number of marbles= 3 +4 +2 = 9
Total number of favourable cases = 3+4=7
P (not an orange marble) = $\frac{7}{9}$

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A bag contains three green marbles, four blue marbles, and two orange marbles. If a. marble is picked at random,then the probability that it is not an orange marble is

The correct option is D 79Total number of marbles= 3 +4 +2 = 9 Total number of favourable cases = 3+4=7P (not an orange marble) =79

The correct option is D $\frac{7}{9}$
Total number of marbles= 3 +4 +2 = 9
Total number of favourable cases = 3+4=7
P (not an orange marble) = $\frac{7}{9}$