A ball mass 0.2kg moving with a velocity of 4m/s hits a wall and bounces back with a velocity of 3m/s. What is the change in momentum

Open in App

Solution

V=4, U=-3 Final momentum - initial moment MV-MU= M (V-U) = 0.2(4-(-3))=1.4kgm/s

Suggest Corrections

Similar questions

A football of mass 5 kg moving with a velocity of 10 m/s hits a pole and, the ball bounces back with a velocity of 5m/s. Find the change in momentum and the force exerted on the ball, if the force acts for 0.02s.

Q. A ball hits a wall with a velocity of

30

m / s

and re bounces with same velocity. What is change in its velocity.

Q. A rubber ball of mass 250 g hits a wall normally with a velocity

10 m s^{- 1}

and bounces back with a velocity of

8 m s^{- 1}

. The impluse is _______N s.

Q. A

0.5 k g

ball moving with a speed of

12 m / s

strikes a hard wall and return back with same velocity. Find change in momentum.

Q. A rubber of mass

200

g hits a wall normally with a velocity of

{10 m s}^{- 1}

and bounces back with a velocity of

{8 m s}^{- 1}

. The impulse is _____ Ns.

Join BYJU'S Learning Program