A ball of mass $0.2 k g$ is thrown against the wall $,$ the ball strikes the wall normally with velocity of $30 m / s$ sand rebounds with velocity of $20 m / s .$ Calculate the impulse of the force exerted by the ball on the wall

2 N

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- 10 N

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20 N

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40 N

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Solution

The correct option is B $- 10 N$
Given $, u = 30 m / s$ $, v = 20 m / s$
$m = 0.2 k g$
impulse $-$ change in momentum of the body $,$
$= m v - m u = m (v - u)$
$= 0.2 (- 20 - 30) = - 10 N$
Hence,
option $(B)$ is correct answer.

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A ball of mass 0.2kg is thrown against the wall, the ball strikes the wall normally with velocity of 30m/s sand rebounds with velocity of 20m/s. Calculate the impulse of the force exerted by the ball on the wall

The correct option is B −10NGiven ,u=30m/s ,v=20m/s m=0.2kgimpulse − change in momentum of the body,=mv−mu=m(v−u)=0.2(−20−30)=−10NHence,option (B) is correct answer.

A ball of mass $0.2 k g$ is thrown against the wall $,$ the ball strikes the wall normally with velocity of $30 m / s$ sand rebounds with velocity of $20 m / s .$ Calculate the impulse of the force exerted by the ball on the wall

The correct option is B $- 10 N$
Given $, u = 30 m / s$ $, v = 20 m / s$
$m = 0.2 k g$
impulse $-$ change in momentum of the body $,$
$= m v - m u = m (v - u)$
$= 0.2 (- 20 - 30) = - 10 N$
Hence,
option $(B)$ is correct answer.