A ball of mass 2kg moving with velocity of 10m/s,it stike with wall and the velocity change to 8m/s.what is change in momentum

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Solution

$I n i t i a l m o m e n t u m = 2 \times 10 = 20 . m o m e n t u m a f t e r h i t i n g t h e w a l l = 2 \times (- 8) = - 16 . t h e r e f o r e c h a n g e i n m o m e n t u m = f i n a l m o m e n t u m - i n i t i a l m o m e n t u m = - 16 - 20 = - 36 K g m s^{- 1} .$

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A ball of mass 2kg moving with velocity of 10m/s,it stike with wall and the velocity change to 8m/s.what is change in momentum

Initial momentum= 2×10=20.momentum after hiting the wall=2×-8=-16.therefore change in momentum=final momentum -initial momentum =-16-20= -36 Kg ms-1.

$I n i t i a l m o m e n t u m = 2 \times 10 = 20 . m o m e n t u m a f t e r h i t i n g t h e w a l l = 2 \times (- 8) = - 16 . t h e r e f o r e c h a n g e i n m o m e n t u m = f i n a l m o m e n t u m - i n i t i a l m o m e n t u m = - 16 - 20 = - 36 K g m s^{- 1} .$