You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Acceleration

A block of ma...

Question

A block of mass $10 k g$ is pushed by a force $F$ on a horizontal rough surface moves with an acceleration $5 m s^{- 2}$ . When the horizontal force is doubled, it gets an acceleration of $18 m s^{- 2}$ . Then the coefficient of friction is (assume $g = 10 m s^{- 2}$ )

0.8

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.6

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 0.8
We know:
$m a = F - μ m g$
Case 1:
$5 \times 10 = F - 100 μ$
Case 2:
$18 \times 10 = 2 F - 100 μ$
Solving simultaneously we get:
$F = 130 N, μ = 0.8$

Suggest Corrections

Similar questions

Q. A body of mass

2 k g

is moving on a rough horizontal surface with an acceleration of

5 m s^{- 2}

and when the horizontal force is doubled, it gets an acceleration of

18 m s^{- 2}

. Then the coefficient of friction between the body and the horizontal surface is : (assume

g = 10 m s^{- 2}

)

Q. A block of weight

100 N

is pushed by a force

F

on a horizontal rough plane moves with an acceleration

1 m / s^{2}

, when force is doubled its acceleration becomes

10 m / s^{2}

. The coefficient of friction is____

(g = 10 m s^{- 2})

Q. A body of mass 10 kg lies on a rough horizontal surface. When a horizontal force of F newtons acts on it, it gets an acceleration of

5 m / s^{2}

. And when the horizontal force is doubled, it gets an acceleration of

18 m / s^{2}

. The coefficient of friction between the body and the horizontal surface is (Take

g = 10 m / s^{2}

)

Q. A block of weight

100

N is pushed by a force

F

on a horizontal rough plane moves with an acceleration

1

m / s^{2}

, when force is doubled it's acceleration becomes

10

m s^{- 2}

. The coefficient of friction is:
(

g = 10

m s^{- 2}

)

Q. A block of mass

10 kg

is placed on rough horizontal surface whose coefficient of friction is

0.5

. If a horizontal force of

100 N

is applied on it along the surface , then acceleration of block will be [Take

g = 10 {ms}^{- 2}

]

Join BYJU'S Learning Program

A block of mass 10kg is pushed by a force F on a horizontal rough surface moves with an acceleration 5ms−2. When the horizontal force is doubled, it gets an acceleration of 18ms−2. Then the coefficient of friction is (assume g=10ms−2)

The correct option is C 0.8We know:ma=F−μmgCase 1:5×10=F−100μCase 2:18×10=2F−100μSolving simultaneously we get:F=130N, μ=0.8

A block of mass $10 k g$ is pushed by a force $F$ on a horizontal rough surface moves with an acceleration $5 m s^{- 2}$ . When the horizontal force is doubled, it gets an acceleration of $18 m s^{- 2}$ . Then the coefficient of friction is (assume $g = 10 m s^{- 2}$ )

The correct option is C 0.8
We know:
$m a = F - μ m g$
Case 1:
$5 \times 10 = F - 100 μ$
Case 2:
$18 \times 10 = 2 F - 100 μ$
Solving simultaneously we get:
$F = 130 N, μ = 0.8$