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Question

A body of mass 1 kg is projected at an angle 30 with horizontal on a level ground at a speed 50 m/s. The magnitude of change in momentum of the body during its flight is
(g=10 m/s2)

A
50 kg ms1
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B
100 kg ms1
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C
25 kg ms1
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D
Zero
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Solution

The correct option is A 50 kg ms1

We know that in a horizontal plane, Initial velocity of projectile = Final velocity of projectile
pi=mucosθ^i+musinθ^jpf=mucosθ^imusinθ^j|Δp|=|pfpi|=2musinθ
=2×1×50×12=50 kg ms1
Alternate Solution:
In the horizontal direction, momentum p doesn’t change.

Δpx=0
In vertical direction,
Δpy=musinθ(musinθ)=2musinθ
=2×1×50×12=50 kg ms1

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