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Question

A body travels for 15 sec starting from rest with constant acceleration. If it travels distances s1,s2 and s3 in the first five seconds, second five seconds and next five seconds respectively, the relation between s1,s2 and s3 is

A
s1=13s2=15s3
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B
s1=15s2=13s3
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C
2s1=13s2=15s3
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D
s1=16s2=15s3
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Solution

The correct option is A s1=13s2=15s3
Since the body starts from rest. Therefore, u=0
s1=12a(5)2=25a2
and,
s1+s2=12a(10)2=100a2s2=100a2s1=75a2

Also,
s1+s2+s3=12a(15)2=225a2s3=225a2s2s1=125a2

taking the ratio for all three distances, we get s1=13s2=15s3

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