A body travels for 15sec starting from rest with constant acceleration. If it travels distances s1,s2 and s3 in the first five seconds, second five seconds and next five seconds respectively, the relation between s1,s2 and s3 is
A
s1=13s2=15s3
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B
s1=15s2=13s3
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C
2s1=13s2=15s3
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D
s1=16s2=15s3
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Solution
The correct option is As1=13s2=15s3 Since the body starts from rest. Therefore, u=0 ⇒s1=12a(5)2=25a2 and, s1+s2=12a(10)2=100a2⇒s2=100a2−s1=75a2