A bullet train starts from rest, and acquires a speed of $25 m s^{- 1}$ in $20 s$ . Assuming uniform acceleration calculate the distance covered by the train in $20 s$ .

1000 m

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100 k m

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10 k m

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100 m

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Solution

The correct option is D $100 m$
Given: initial velocity $u = 0 m s^{- 1}$ , final velocity $v = 25 m s^{- 1}$ , time $t = 20 s$
Let acceleration of train be $a$ , distance travelled $s$ .

Here we do not have the value of acceleration. We will calculate that using, $a = \frac{v - u}{t} = \frac{25 - 0}{20} = 1.25 m s^{- 2}$
Now using, third equation of motion,
$v^{2} - u^{2} = 2 a s$
$25^{2} - 0^{2} = 2 \times 1.25 \times s$
Or $s = \frac{625}{2.50} = 250 m$

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A bullet train starts from rest, and acquires a speed of 25 ms−1 in 20 s. Assuming uniform acceleration calculate the distance covered by the train in 20 s.

A bullet train starts from rest, and acquires a speed of $25 m s^{- 1}$ in $20 s$ . Assuming uniform acceleration calculate the distance covered by the train in $20 s$ .