A can do a piece of work in 40 days and B can do the same piece of work in 60 days. A and B started the work together, in the first 15 days A worked with 50% of his efficiency and in the next 15 days B worked with 50% of his efficiency. In how many days does the remaining work will be completed if both of them work with their full efficiencies?

1 Day

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1.5 Days

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2 Days

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2.5 Days

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Solution

The correct option is B 1.5 Days
15(1/80+1/60) + 15(1/120+1/40) + x*(1/40+1/60) = 1
X= 3/2 = 1.5

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The correct option is B 1.5 Days15*(1/80+1/60) + 15*(1/120+1/40) + x*(1/40+1/60) = 1 X= 3/2 = 1.5

The correct option is B 1.5 Days
15(1/80+1/60) + 15(1/120+1/40) + x*(1/40+1/60) = 1
X= 3/2 = 1.5