A car starts from rest and moves along the x-axis with a constant acceleration $5 m s^{- 2}$ for $8 s$ . If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

160 m

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240 m

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320 m

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400 m

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Solution

The correct option is D 320 m
The distance travelled in first eight seconds $= x_{1} = 0 + \frac{1}{2} * 5 * 8^{2} = 160 m$
At this point the velocity $v = u + a t = 0 + 5 \times 8 = 40 m s^{- 1}$
Therefore, the distance covered in last four seconds, $x_{2} = 40 \times 4 = 160 m$
Thus, the total distance $x = x_{1} + x_{2} = 160 + 160 = 320 m$

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A car starts from rest and moves along the x-axis with a constant acceleration 5 ms−2 for 8 s. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?

The correct option is D 320 mThe distance travelled in first eight seconds =x1=0+12∗5∗82=160 mAt this point the velocity v=u+at=0+5×8=40 ms−1Therefore, the distance covered in last four seconds, x2=40×4=160mThus, the total distance x=x1+x2=160+160=320m

A car starts from rest and moves along the x-axis with a constant acceleration $5 m s^{- 2}$ for $8 s$ . If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from rest?