The correct option is B ₹50
If we analyse the question carefully, we get to know that the amount Ramu has to pay for each hour forms an arithmetic progression.
The first term, a of the AP is 20, which is the charge for the first hour.
The common difference, d of the AP is 10, which is the amount charged for each additional hour.
i.e., a=20 and d=10
Since Ramu plays games for 4 hours, he has to pay the amount equivalent of the 4th term of this AP.
Since nth term of the AP is given by
an=a+(n−1)d,
we have a4=20+(4−1)10.
⟹a4=50
Hence, Ramu must pay a total of ₹50.