A farmer moves along the boundary of a square field of side 10 metre in 40 sec. What will be the magnitude of displacement of the farmer at the end of 2 minutes in 20 sec.from his initial position?
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Solution
Total distance covered 10m in 40sec Total time taken= 2min 20sec= 140sec Total round completed = 140/40=3.5 rounds
So If an object moves from A to D, the shortest path will be from A to C. So displacement is AC, that we will find by phythogoras theorem.