A gas initially at 0 °C is heated so that its pressure and volume are both increased by Y times. If its final temperature is 819 °C, then calculate the value of Y.

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Solution

The correct option is B 2
$P_{1} = P; V_{1} = V; and T_{1} = 0 + 273 = 273 K P_{2} = YP; V_{2} = YV; and T_{2} = 819 + 273 = 1092 K$
As per combined gas law equation , we get :
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}} \frac{PV}{273} = \frac{YP \times YV}{1092} Y^{2} = \frac{1092}{273} Y^{2} = 4 Y = 2$

Thus , volume and pressure both have become twice of their initial value.

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