A given amount of gas A is confined in a chamber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg.

1. What is the temperature, when the pressure is 10 cm Hg?
2. What will be the pressure, when the chamber is brought to $100^{\circ} C$ ?

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Solution

At constant volume,

1. $\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

Here, $P_{1} = 100 c m, T_{1} = 0^{o} C = 273 K, P_{2} = 10 c m$

Then, $T_{2} = \frac{10 \times 273}{100} = 27.3 K$

2. $\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

Here, $P_{1} = 100 c m, T_{1} = 0^{o} C = 273 K, T_{2} = 100^{o} C = 373 K$

Then $P_{2} = \frac{100 \times 373}{273} = 136.63 c m H g$

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Q. A given amount of gas A is confined in a chamber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg. What will be the pressure, when the chamber is brought to

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A given amount of gas A is confined in a chamber of constant volume. When the champber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg.
(a) What is the temperature, when the pressure is 10 cm Hg?
(b) What will be the pressure, when the chamber is brought to $10^{\circ} C .$