A given amount of gas A is confined in a chamber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg. What will be the pressure, when the chamber is brought to $100^{\circ} C$ ?

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Solution

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$
Here, $P_{1} = 100 c m, T_{1} = 0^{o} C = 273 K, T_{2} = 100^{o} C = 373 K$
Then $P_{2} = \frac{100 \times 373}{273} = 136.63 c m H g$

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A given amount of gas A is confined in a chamber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg. What will be the pressure, when the chamber is brought to 100∘C?

P1T1=P2T2 Here, P1=100 cm, T1=0oC=273K, T2=100oC=373KThen P2=100×373273=136.63 cm Hg

A given amount of gas A is confined in a chamber is immersed in a bath of melting ice, the pressure of the gas is 100 cm Hg. What will be the pressure, when the chamber is brought to $100^{\circ} C$ ?

$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$
Here, $P_{1} = 100 c m, T_{1} = 0^{o} C = 273 K, T_{2} = 100^{o} C = 373 K$
Then $P_{2} = \frac{100 \times 373}{273} = 136.63 c m H g$