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Domestic Electric Circuits

A household u...

Question

A household uses the following electric appliance
a. Refrigerator of rating 400w for 10hrs.
b. Two electric fans of rating 80w each for 12hrs each day.
c. 6 electric bulbs of rating 18w each for 6hrs each day.
Calculate the electric bill of the house for the month of June if the cost of per unit electrical energy is₹3.0

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Solution

Energy consumed by the fridge in a day = 40010 = 4000 Wh = 4 kWh
Energy consumed by the two fans in a day = 2(8012) = 1920 Wh = 1.92 kWh
Energy consumed by the six bulbs in a day = 6(186) = 648 Wh = 0.648 kWh
Total energy consumed in one day = 4 + 1.92 + 0.648 = 6.568 kWh

Total energy consumed in the month of June = 30 days 6.568 kWh = 197.04 kWh

Electricity bill ( cost ) = Rs.3 *197.04 = Rs.591.12.

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