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General Gravity Problem

a juggler kee...

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a juggler keeps 5 balls going with one hand so that at any instant 4 balls are in air and one in hand.if each raises to a height of 20 m then the time for which ball stays in the hand

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Q. A juggler keeps 5 balls going with one hand, so that at any instant, 4 balls are in air and one ball in the hand. If each ball rises to a height of 20 m, then the time for which each ball stays in the hand is

(g = 10 {m s}^{- 2})

Q. A juggler keeps

5

balls going with one hand , so that at any instant,

4

ball in the hand. If each ball rises to a height of

20

m, then the time for which each ball stays in the hand is

(g = 10 m / s^{2})

Q. A juggler keeps n balls going with one hand, so that at any instant, (n-1) balls are in air and one ball in the hand. If each ball rises to a height of x metres, the time for each ball to stay in his hand is

Q. A juggler maintains four balls in the air with air with throwing speed

20

m/s upwards in regular time intervals. When one ball is about to leave his hand the height of balls in air from the ground will be:

Q. A juggler keeps on moving four balls in air throwing the balls after regular intervals. When one ball leaves his hand (speed

= 20 m s^{- 1}

), the position of other balls (height in metre) will be :

g = 10 m s^{- 2}

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