A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the Hg, the gas pressure in atm is ?

1.0 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.25 atm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.30 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.45 atm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 1.25 atm
Gas pressure = barometric pressure + pressure due to Hg column
$743 m m H g + (36.2 - 15.5) \times 10 m m H g = 950 m m H g$
$= \frac{950}{760} = 1.25 a t m$

Suggest Corrections

Similar questions

A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the flask reads 15.5 cm. If the barometric pressure is 743 mm Hg, the gas pressure in atm is?

Q. A manometer is connected to a gas containing bulb. the open arm reads

40.0

cm whereas the arm connected to the bulb reads

15.0

cm. If barometric pressure is

74.0

cm Hg, then what is the pressure of a gas in the bar?

Open end mercury manometer is connected to a gas chamber containing gas at a pressure of 1.38 bar. The barometric pressure is 750 mm Hg. Mercury level in the arm connected to a gas chamber stands at 11.3 cm. What is the reading in open arm of the manometer?

Q. When the left arm of a mercury manometer is connected to a cylinder filled with a gas, the level of the mercury in the right arm rises by 2 cm. If the pressure of the gas in the container 110160 Pa, the atmospheric pressure is __________cm of Hg. ( take

g = 10 m s^{- 2}

)

One arm of a glass U-tube is open to the atmosphere, whereas the other vertical arm is connected to a gas supply. The difference in levels of mercury (density = 13.6 g cm^-3) between the vertical arms of the U-tube manometer is h = 3 cm. If the atmospheric pressure is 760 mm Hg and the gravitational acceleration is 9.8 m s^-2, then the pressure of the gas is about:

Join BYJU'S Learning Program

A manometer is connected to a flask containing a gas. The open arm reads 36.2 cm whereas the arm connected to the Hg, the gas pressure in atm is ?

The correct option is B 1.25 atmGas pressure = barometric pressure + pressure due to Hg column 743 mm Hg+(36.2−15.5)×10 mm Hg=950 mm Hg =950760=1.25 atm

The correct option is B 1.25 atm
Gas pressure = barometric pressure + pressure due to Hg column
$743 m m H g + (36.2 - 15.5) \times 10 m m H g = 950 m m H g$
$= \frac{950}{760} = 1.25 a t m$