CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

A mole of N2H4 loses 10 mol of electrons to form a new compound A. Assuming that all the nitrogen appears in the new compound, What is the Oxidation State of Nitrogen in A?


Open in App
Solution

Step 1: Oxidation state:

  • "The oxidation state of an element in a compound ascertained according to a set of rules formulated on the basis that electron pair in a covalent bond belongs entirely to a more electronegative element."

Step 2: Calculation of oxidation state:

  • The oxidation state of N in Hydrazine N2H4is shown below:

2x+4=02x=-4x=-2.

  • If one mole of hydrazine contains two moles of nitrogen and loses 10 moles of electrons, one nitrogen atom loses five electrons.
  • Hence, its oxidation number will increase by 5. Therefore, the oxidation state of N in compound A will be:

OxidationstateofN=(2)+(5)=+3

Thus, the oxidation state of Nitrogen in compound A +3.


flag
Suggest Corrections
thumbs-up
1
BNAT
mid-banner-image