Question

A nuclear reactor containing $U^{235}$ preduces 10 MW. Calculate the fisson rate assuming that 200 MeV of useful energy is released in one fission

• A. $3.1\times {10}^{17}se{c}^{-1}$
• B. $6\times {10}^{8}se{c}^{-1}$
• C. $1.5\times {10}^{17}se{c}^{-1}$
• D. $2\times {10}^{17}se{c}^{-1}$

Answer 1

The correct option is A $3.1\times {10}^{17}se{c}^{-1}$

Power $P=10MW$ means that $P=10\times {10}^{6}Joule/sec=\frac{{10}^7}{1.6\times {10}^{-13}}MeV/s=6.25\times {10}^{19}MeV/s$

So fission needed per second will be $\frac{Power}{\text{energy in one fission}}=\frac{6.25\times {10}^{19}}{200}=3.125\times {10}^{17}/s$

Option A is correct.