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Question

Assuming the energy released per fission of U235 is 200 me V , the energy released in the fission of 1 kg of U235 is energy

A
0.91×1011J
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B
0.91×1013J
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C
8.19×1011J
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D
8.19×1013J
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Solution

The correct option is D 8.19×1013J

Given,

Energy released per atom, E=200MeV=200×106×1.6×1019=3.2×1011J

Number of atom in 1kg uranium, n=mNAM=1000×6.023×1023235=2.56×1024

Total Energy released = nE=2.56×1024×3.2×1011=8.19×1013J

Hence, Total Energy released = 8.19×1013J.


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