Question

A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance $S_1$ in the first 10 sec and a distance $S_2$ in the next 10 sec, then

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

As S= ut + $\frac{1}{2}a{t}^2$

$\therefore S_1=\frac{1}{2}a(10{)}^2=50a$ ..........(i)

The distance traveled in first 20s is

$S=\frac{1}{2}a(20{)}^2=200a$

We have

$S_2=S-S_1=150a$

$\therefore S_1=\frac{S_2}{3}$