A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels a distance S1 in the first 10 sec and a distance S2 in the next 10 sec, then
S1=S23
As S= ut + 12at2
∴S1=12a(10)2=50a ..........(i)
The distance traveled in first 20s is
S=12a(20)2=200a
We have
S2=S−S1=150a
∴S1=S23