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Question

A particle experiences a constant acceleration for 20 s starting from rest. If it travels a distance S1 in the first 10 s and a distance S2 in the next 10 s, then:

A
S1=S2
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B
S1=S23
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C
S1=S22
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D
S1=S24
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Solution

The correct option is B S1=S23
Let the acceleration be a.

S1=ut+12at2
Here, u=0 and the time interval is 10 s.
S1=12a×100
Or, S1=50a ....(i)

Now, speed of the particle at the end of 10 s,
v=u+at
v=10a

So, for the next 10 s,
S2=ut+12at2
S2=100a+50a=150a ....(ii)

From Eq.(i) and (ii),
S1=S23

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