A particle experiences a constant acceleration for 20s starting from rest. If it travels a distance S1 in the first 10s and a distance S2 in the next 10s, then:
A
S1=S2
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B
S1=S23
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C
S1=S22
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D
S1=S24
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Solution
The correct option is BS1=S23 Let the acceleration be a.
S1=ut+12at2
Here, u=0 and the time interval is 10s. ⇒S1=12a×100
Or, S1=50a....(i)
Now, speed of the particle at the end of 10s, v=u+at ⇒v=10a
So, for the next 10s, S2=ut+12at2 ⇒S2=100a+50a=150a....(ii)