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Question

A particle is moving in a circular path of radius 1 m with uniform speed 55ms1 as shown in figure.
The magnitude of change in velocity between points A and B is
1394799_e3df48c2f0aa4a59a2f9b6351d13359d.JPG

A
Zero
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B
20ms1
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C
102ms1
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D
35ms1
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Solution

The correct option is C 102ms1
Given is a uniform circular motion, with constant speed =55 m/s velocity at A(vA)=(55^j)m/s


velocity at B(vB)=55(cos37j+sin37^1)m/s

=5(3^i+4^j)m/s

Thus, change in velocity =vBvA=[5(3^i+4^j)55^j]m/s=5(3^i9^j)m/s

Hence, required magnitude =532+92 m/s . =152 m/s

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