A particle moves with a velocity 5¯i−3¯j+6¯k m/s under the influence of a constant force →F=(10¯i+10¯j+20¯k)N. The instantaneous power applied to the particle is
A
200 J/S
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B
40 J/S
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C
140 J/S
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D
170 J/S
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Solution
The correct option is C 140 J/S p=→F.→V=(5¯i−3¯j+6¯k).(10¯i+10¯j+20¯k)=50−30+120=140J/S